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11x^2-1020x-11200=0
a = 11; b = -1020; c = -11200;
Δ = b2-4ac
Δ = -10202-4·11·(-11200)
Δ = 1533200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1533200}=\sqrt{400*3833}=\sqrt{400}*\sqrt{3833}=20\sqrt{3833}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1020)-20\sqrt{3833}}{2*11}=\frac{1020-20\sqrt{3833}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1020)+20\sqrt{3833}}{2*11}=\frac{1020+20\sqrt{3833}}{22} $
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